Question

If a person applies 80 N force at the handle of a door that is 2.5 m from

the hinge, what is the moment of force​

Answer 1

Answer:

200 Nm

Explanation:

moment of force (or Torque) = 1 of the force * perpendicular distance from the axis of rotation * angle b/w force and displacement

moment ( T ) = F * r * cos  (theta)

OR

T = F . r

here theta is 0

therefore

T = Fr

 = 80 * 2.5

  =200 Nm

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hope it help u

Answer 2

Answer:

$\bigstar{\bold{Moment\:of\:force=200\:Nm}}$

Explanation:

$\Large{\underline{\underline{\it{Given:}}}}$

• Force (F) = 80 N
• Distance (d) = 2.5 m

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Moment of force ($\tau$)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ The equation for finding moment of force is given as

Moment of force = Force × Distance

Moment of force = 80 × 2.5

Moment of force = 200 Nm

$\boxed{\bold{Moment\:of\:force=200\:Nm}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The moment of force is given by

 $\tau$ = F × d

where F is the force and dis the perpendicular distance.