Chemistry, asked by paljpatel6, 1 month ago

If a person burns 2171 Cal each day, how much energy (kJ) does she burn in 2 days?

Answers

Answered by muhammadjahanzeb123
0

Answer:

2 × 2171= 4342× 4.184=18166.98 kj

Explanation:

first multiply 2171 with 2 because it asking about two days so you will get 4342 cal. 1 cal equal to 4.184 kj. so to convert cal to kj multiply the answer with 4.184kj to get answer in kj.

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