Question

if a person buys a lottery ,chance of winning a Toyota car is 60%,chance of winning Hyundai car is 70% and chance of winning both is 40% , then chance of winning Toyota or hyundai is ? follow me ​

Answer 1

Answer:

0.9 is the answer

Step-by-step explanation:

here we will use the following fomula

i.e. P(T U H)=P(T)+P(H)-P(T ∩ H)

where AND represents Intersection and OR represents Union.

1. P(T)=60%=6/10P(H)=70%=7/10
2. P(T and H)=40%=4/10
3. P(TUH)=6/10+7/10-4/10
4. =0.6+0.7-0.4

Answer 2

The correct answer to the question is 0.9

So, we can say that the chance of winning Toyota or hyundai is 0.9

Step-by-step explanation:

Given -

Probability of winning toyota = p(T) = 60%=6/10

Probability of winning Hyundai = P(H)=70%=7/10

Probability of winning both =P(TUH)= 40%=4/10

Hence, the chance of winning either one = P(T ∩ H)

Formula to be used -

P(T U H)=P(T)+P(H)-P(T ∩ H)

P(TUH)=6/10+7/10-4/10

=0.6+0.7-0.4

= 0.9