. If a person had walked 1 km/hr faster, he would have taken 15 minutes less to walk 3 km.Find the original rate of his walking.
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Distance= 3 km
Original Speed = X km/hr
Original time = T hr
When speed is X km/hr :-
D=S×T
X = 3/ T
When speed is X+1 km/hr :-
3 =( X+1) × (T-15/60)
3 = (3/T + 1) × (T - 1/4)
(3+T) × ( 4T-1)
3 = ------- ---------
T 4
4T×3 = 12T - 3 + 4Tsq. - 1
12T = 12T - 3 + 4Tsq. - 1
3+1 = 4Tsq.
T = 1 hr
X = D/T
X = 3 / 1 = 3 km/hr.
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