Question

If a person increases his speed by 83(/)%,what will be the percentage reduction in time taken to reach the same destination?​

Answer 1

Answer:

distance= speed*time

If speed increases by 83.33%, new speed will be s*1.33

then time will be reduced 1/1.83≈0.75 times or by 54%

Answer 2

Given: the speed is increased by 83%.

To find: the reduction in time taken.

Step-by-step explanation:

Step 1 of 2

Let the initial speed and time be $v_{1}$ and $t_{1}$, respectively.

The distance will remain same, let it be $d$.

The final speed is 83% more to that of initial speed so, it will be equal to:

$v_{2} =(1+0.83)v_{1}$

Step 2 of 2

The formula of distance is distance=speed x time.

$d=v_{1}t_{1}$                                                ...(i)

Also, $d=v_{2} t_{2} =1.83v_{1} t_{2}$                     ...(ii)

Equating equations (i) and (ii)

$v_{1} t_{1}=1.83v_{1} t_{2}\\t_{1}=1.83 t_{2}\\ t_{2}=\frac{1}{1.83} t_{1}\\ t_{2}=0.5464t_{1}$

The time will be reduced by 54.64% when speed is increased by 83%.