If a person is pulling upon a rope that is atttached to a wall with a force of 500 newton then what will be the force due to the wall ?
Answers
Answer:
Following Newton's third law (... equal and opposite forces...), the string stretches until it reaches its tightest point.
You might imagine this to be like a tug-of-war game with both sides dead even.
Since we are focusing on horizontal forces, and since exactly two horizontal forces are pulling in opposite vector directions to the same extent, these cancel each other out, as seen here:
∑
F
x
=
T
−
F
x
=
m
a
x
=
0
As stated in the question, it would mean that
T
=
FWhile many people would like to simply add the forces from each end to get a total force, this is fundamentally incorrect.
This is an application of Newton's Third Law: "For every action there is an equal and opposite reaction." The only way someone on one end of the string can exert a force of 10 N on the other end of the string is of the other end of the string exerts a 10 N force in the opposite direction.
Suppose I hang a 1 kg mass from a spring scale. This pulls with a force of approximately 10 N. Next, remove the weight and attach the spring scale to a wall. Pull on the scale until it reads 1 kg. That's the same 10 N force that the weight (and gravity) exerted downward when it was hanging. Lastly, consider what would happen if you attached a second spring scale to the wall and the end of the string to that spring scale. When you pull one hard enough to make it read 1 kg, the spring scale on the opposite end will also show 1 kg. They are indicating equal forces in opposite directions.
x
(so
T
−
F
x
=
0
). Thus, if
F
x
=
10 N
,
T
=
10 N
.
(Additionally, even if
m
is small,
a
x
must therefore be
0 m/s
2
.)
Explanation:
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Answer:
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