Question

If a person travels from A to B at 75km/h In a car .In return journey the speed reduced by 15km/h. If the total time taken is four and half hours . Then the distance(inkm) between A and B​

Answer 1

Answer:

given s1=75kmph

reduced 15kmph s2 =60kmph

avg speed = 2xy/x+y

2×75×60/75+60

150×60/135

10×60/9

600/9

200/3

speed=200/3

time= 4.5hrs

speed=distance/time

distance=speed×time

distance=200/3×9/2

d=100×3=300kms is answer

Step-by-step explanation: