if a person walk from x to Y at the speed of 40 km per hour and when he returns from Y to x he increases his Speed 50% so find the average speed of both journey
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Solution:
Speed from X to Y = 40 km/hr
Speed from Y to X = 1.5 × 40 = 60 km/hr
Therefore, Average Speed
= 2 × 40 × 60 / (40+60)
= 4800/100
= 48 km/hr
Hence, Average Speed of the person is 48 km/hr
Hope you got it!
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But friend I have 1 question to you - How could a person is able to "walk" at a speed of 40 & 60 km/hr??
Speed from X to Y = 40 km/hr
Speed from Y to X = 1.5 × 40 = 60 km/hr
Therefore, Average Speed
= 2 × 40 × 60 / (40+60)
= 4800/100
= 48 km/hr
Hence, Average Speed of the person is 48 km/hr
Hope you got it!
.
.
But friend I have 1 question to you - How could a person is able to "walk" at a speed of 40 & 60 km/hr??
ravidubey75:
I also don't know how would a person walk 40 & 60 km per hour but it is a real question
OK, atleast you got it. A person can walk at the most at 4 to 5 km/hr.
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