Question

if a person walks from his house to his office at 4km/hr, he is 4 minutes late if he walks at 6km/hr. he is 2 minute6 early. find the distance between the person's house and office?​

Answer 1

Answer:

Let the actual time be 't'

and distance be x

Now according to first condition, we have

x/4 = t+5/60

​ And according to Second condition, we have

x/5=  t−  10/60

​ 60x=4t+20

60x=5t−50

Subtracting equation 1 from 2, we have

0=t−70

∴t=70

Putting the value of t we get x=5km