if a person wear lens of power -6D for distant vision and for correcting is near vision he need a lens of 2D. determine the focal length of lenses in both cases??
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D=1/f so - 6=1/f
=f=-1/6= - 1.66
2nd case,
D=1/f so 2=1/f and f=1/2=0.5
=f=-1/6= - 1.66
2nd case,
D=1/f so 2=1/f and f=1/2=0.5
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