Question

If a person weight is 8000 gram, run from goal pst to the other post at a speed of 4m/sec and 6m/sec in 1 min calculate - i Acceleration
ii Force applied​

Answer 1

Answer:

1. 1/30 m/sec²

2.4/15 N

Explanation:

1.

acceleration =

(final velocity - initial velocity)/Time taken

acceleration = (6-4)/60 = 1/30

2.

Force = mass × acceleration

Force = (8) × 1/30 = 4/15 N

Answer 2

Explanation:

Initial velocity(u) - 4m/s

Final velocity(v) - 6m/s

Time (t) = 1 min = 60seconds

Acceleration = v - u / t

= 6 - 4/60

= 2/60

= 1/30 m/s square

Force applied = mass × Acceleration

= 8000 × 1/30

= 2.6 N (approximately)

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