Question

if a person will sell a thing with ₹64 more than its actual price then instead of getting 6% loss he will get 10% profit then what is actual price of that thing​

Answer 1

Step-by-step explanation:

selling price =x + 64

first condition 6% loss =94 & second condition 10% profit= 110

so, x + 64* 110 /94 = X

110x + 64*110= 94x

110X-94x = 64*110

16x= 64*110

X=440

Answer 2

Answer:

The Actual Price was Rs.640.

Step-by-step explanation:

Let the C.P be Rs.x

Then,

S.P = x + 64

Now,

Profit = S.P - C.P

P = (x + 64) - x

P = x - x + 64

P = 64

Now,

Profit % = (P/C.P) × 100

But given,

P % = 10%

So,

10 = (64/x) × 100

10/100 = 64/x

(1/10) = (64/x)

Cross multiplying we get

1 × x = 64 × 10

x = 640

Hence,

C.P = Rs.640

Therefore,

The Actual Price was Rs.640.

Hope it helped and believing you understood it........All the best