if a piece of work can be completed in 18 days by 10 men ,working 6 hrs per day.how many day must 15 men work to complete the same work in 12 days
day.
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let the required numbers of hours per day be x .
more men , less hours per day ( inverse proportion )
men -15:10
days - 12 : 18 :: 6: x
=> 15 × 12× x = 10 ×18×6
=> 10 ×18 × 6 / ( 15 × 12 )
x = 6
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