Question

If a pipe, 48m long, is divided into two parts in the ratio
1/7:1/5
then the length of the largest part is
meters.
2) 20
2) 28
3) 7
4) 5​

Answer 1

Answer:

Given :-

If a pipe, 48m long, is divided into two parts in the ratio

1/7:1/5

To Find :-

Length of largest pipe

Solution :-

Let the ratio be 1x/7:1x/5

Now

x/7 + x/5 = 48

5x + 7x/35 = 48

12x/35 = 48

12x = 48 × 35

12x = 1680

x = 1680/12

x = 140

Larger part = x/5 = 140/5 = 28

Answer 2

Given that:

• A pipe, 48 m long is divided into two parts in the ratio 1/7 : 1/5.

To Find:

• The length of the largest part in meters.

Converting the ratio:

• Ratio = 1/7 : 1/5
• Ratio = (1/7) / (1/5)
• Ratio = (1 × 5) / (1 × 7)
• Ratio = 5 / 7
• Ratio = 5 : 7

Let us assume:

• The length of the shortest part be 5x.
• The length of the largest part be 7x.

Finding the length of each part:

According to the question.

→ 5x + 7x = 48

→ 12x = 48

→ x = 48/12

→ x = 4

Shortest part = 5x = 5(4) = 20

Largest part = 7x = 7(4) = 28

Hence,

• The length of the largest part is 28 m.