If a pipe can fill a tank in 2 hrs. and
another pipe can fill the same tank in
6 hrs. then what part of a tank will be
filled by both pipes in 1 hr., if they are
opened simultaneously ?
Answers
Answer:
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).Then the 1st pipe pours in 2 units/hr and 2nd pipe pours in 1 unit/hr (simple maths -> 12units/6hrs is 2units/hr).
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).Then the 1st pipe pours in 2 units/hr and 2nd pipe pours in 1 unit/hr (simple maths -> 12units/6hrs is 2units/hr).If both pipes are opened at same time, units filled per hour is 2+1 = 3 units/hr.
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).Then the 1st pipe pours in 2 units/hr and 2nd pipe pours in 1 unit/hr (simple maths -> 12units/6hrs is 2units/hr).If both pipes are opened at same time, units filled per hour is 2+1 = 3 units/hr.Thus time taken to fill 12 unit capacity of tank is 12 units/(3 units/hr) = 4 hours!
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).Then the 1st pipe pours in 2 units/hr and 2nd pipe pours in 1 unit/hr (simple maths -> 12units/6hrs is 2units/hr).If both pipes are opened at same time, units filled per hour is 2+1 = 3 units/hr.Thus time taken to fill 12 unit capacity of tank is 12 units/(3 units/hr) = 4 hours!That’s your answer -> 4 hours.
Let's assume for simplicity that the tank has a capacity of 12 units (lcm of 6 & 12, unit can be litres or gallons or anything- just call this unit).Then the 1st pipe pours in 2 units/hr and 2nd pipe pours in 1 unit/hr (simple maths -> 12units/6hrs is 2units/hr).If both pipes are opened at same time, units filled per hour is 2+1 = 3 units/hr.Thus time taken to fill 12 unit capacity of tank is 12 units/(3 units/hr) = 4 hours!That’s your answer -> 4 hours.Alternately, you can just use the formula 6*12/(6+12) = 72/18 = 4hrs.
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Step-by-step explanation:
Time taken by 1st pipe to fill the tank =2 hr
work done by 1st pipe in 1 hr=1/2
Time taken by 2nd pipe to fill the tank = 6 hrs
work done by 2nd pipe in 1 hr =1/6
work done by both 1st pipe and 2nd pipe in 1 hr=1/2+1/6=4/6=2/3