If a pipe can fill a tank in 2 hrs. and
another pipe can fill the same tank in
6 hrs. then what part of a tank will be
filled by both pipes in 1 hr., if they are
opened simultaneously ?
Answers
Answered by
3
If both pipes are opened at same time, units filled per hour is 2+1 = 3 units/hr.
Thus time taken to fill 12 unit capacity of tank is 12 units/(3 units/hr) = 4 hours!
That’s your answer -> 4 hours.
Alternately, you can just use the formula 6*12/(6+12) = 72/18 = 4hrs.
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