Question

If a pipe can fill a tank in X hours and another pipe can empty the full tank in Y hours (where y>x), then on opening both the pipes, the net part filled in 1 hour = (1/y)-(1/x)​

Answer 1

$work \: done \: by \: the \: pipe \: filling \: \\ the \: tank \: in \: 1 \: hour = \frac{1}{x} \\ work \: done \: by \: the \: pipe \: emptying \\ the \: tank \: in \: 1 \: hour = \frac{1}{y} \\ net \: part \: of \: the \: tank \: filled \\ \: in \: 1 \: hour = \frac{1}{x} - \frac{1}{y} = \frac{y - x}{xy} \\ \therefore \: the \: tank \: will \: be \: filled \\ \: in \: ( \frac{xy}{y - x}) hours$

$Hope \: it \: clear! \: \\ \\ </p><p></p><p>keep \: learning \: ,keep \: studing!!</p><p>$