If a pipe removes water at some distance with a speed of 2m/sec. In time 2.0minutes.Then find the distance up to which the water reach the far point?
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distance = time x speed
= (2 x 120) x 2 (∴ i toke 2 x 120 because they have told 2 m/sec
so 2 min is equal to 120 sec)
= 240 x 2
= 480 m
∴ after 480 meters the pipe reaches the far point.
= (2 x 120) x 2 (∴ i toke 2 x 120 because they have told 2 m/sec
so 2 min is equal to 120 sec)
= 240 x 2
= 480 m
∴ after 480 meters the pipe reaches the far point.
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