Question

If a plane is inclined at an angle 50 with the horizontal and a cylindrical metal is allowed to roll between two fixed height 92cm apart on the plane. Given that the acceleration of the cylinder should be (2gSinθ/3). [Take g as 9.8m/s2] Find the acceleration of the cylinder?

Answer 1

Answer:

The distance of 10 m on the hypotenuse on an incline of 30

0

corresponds to a height difference of 5. Thus change in potential energy is given as 5mg.

The change in the kinetic energy is given as

2

1

mv

2

+

2

1

Iω

2

moment of inertia of a hollow cylinder about centroidal axis is mr

2

Thus we get the kinetic energy as

2

1

mv

2

+

2

1

mr

2

r

2

v

2

or

mv

2

Equating both the energies we get

5mg=mv

2

or

v=

49

=7m/s

Explanation:

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