Question

If a plane is inclined at an angle 5o with the horizontal and a cylindrical metal is allowed to roll between two fixed height 92cm apart on the plane. Given that the acceleration of the cylinder should be (2gSinθ/3). [Take g as 9.8m/s2] What exactly is the acceleration of the cylinder?

Answer 1

0.61 second is the correct answer to the give question .

Explanation:

As mention in the question

The inclination of the plane, i.e θ = 50°

Also given the Height i.e h1 = s1 = 92 cm

= 0.92 m

Given g = 9.8 m/s²

The Acceleration of the cylinder is given as

$Acceleration\ (a)=\frac{2}{3} \ * g *sin\theta$

where g= gravity

By using the 2nd equation of the motion that is written as

$s\ = \frac{1}{2} * a \ * t^{2}$

⇒ $0.92 \ = (9.8 * sin\ \frac{50}{3}) * t^{2}$

= $t^{2} = \frac{2.76}{9.8*0.76}$

=$t^{2} = 0.37$

=$t = 0.61 second$

Therefore the acceleration of the cylinder=0.61 second

Learn More :

• brainly.in/question/17482569