If a planet consists of a satellite whose mass and radius are both half that of earth. Acceleration due to gravity (g) at its surface should be :
Answers
Answered by
8
Hey.
Here is the answer.
As g= GM / R^2...............on earth
but at that planet
M' = M/2
R'= R/2
so, g' = GM'/ R'^2 = 4GM/ 2 R^2 = 2GM/R^2
so, Acceleration due to gravity (g) at its surface should be twice that on the earth.
Thanks.
Here is the answer.
As g= GM / R^2...............on earth
but at that planet
M' = M/2
R'= R/2
so, g' = GM'/ R'^2 = 4GM/ 2 R^2 = 2GM/R^2
so, Acceleration due to gravity (g) at its surface should be twice that on the earth.
Thanks.
Answered by
0
Answer:
19.6 m/s²
Explanation:
- Acceleration due to gravity, g=GM/R²
- g is proportional to M/R²
denote mass of earth as Me and that of other planet as Mp and radius as Re and Rp. acceleration due to gravity as ge and gp.
for planet ,Mp=Me/2
and Rp=Re/2
ge/gp=(Me/Mp)(Re/Rp)²
=1/2×2²=2
so gp=2×ge=2×9.8
=19.6m/s²
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