If a planet has an eccentricity of 0.92 and a distance of the major axis is 5,000,000 km, then what is the distance between foci?
460,000,000 km
0.00000018 km
4,600,000 km
5,000,000 km
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Answer:
Focus = a×e
where e is eccentricity and a is half of major axis.
F = 2500000 × 0.92
= 2300000
Distance b/w foci is 2f
= 2×2300000
= 4600000km
Option C
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