Question

if a platinum wire is stretched by 0.5% what is the strain of the wire​

Answer 1

Answer:

0.005

Explanation:

here the explanation

Answer 2

Explanation:

• Strain for any object is the ratio of change in dimension of the object with respect to the original dimension of the object.

• Let suppose, a force $F$ act on an object of length $l$, initially, for some time the object bears the pressure but after some time, it begins to yield or change its dimension under the action of the external force.

• This force is said to be directional in a such a way that the new modified object bears the minimum force.

• Hence, the strain for this object will be the ratio of change in length of the object to the length of the initial object.

Now,

According to the question,

Let's assume the initial length of the Platinum wire is $l$ and under some external force, the length of the wire increases to $0.5%$% of the initial length.

Initial length $=l$

The new length becomes,

$l'=l+0.5$% × $l$

$l'=l+\frac{0.5}{100}l$

$l'=\frac{100.5l}{100}$

$l'=1.005l$

Hence, the new length of the wire is $1.005l$ , therefore, change or increase in length that is $dl$ will be

$dl=l'-l$

$dl=1.005l-l$

$dl=0.005l$

Now,

The strain produced in the object is given by

$S=\frac{dl}{l}$

$S=\frac{0.005l}{l}$

$S=0.005$

Since, strain is the ratio of two similar quantities, it is a dimensionless quantity or it does not have any units.

Final answer:

Hence, the strain produced in the wire is 0.005.