Question

if a point (-1/2,1/3) lies on the graph of -2x = 2ay -10 what is value of a

a) 2/33

b) 43/5

c) 33/2

d ) 54/6​

Answer 1

Step-by-step explanation:

Given equation is 2x−y+k=0

Given point (−1,3)

Accoding to question the point lies on line

2(−1)−3+k=0

−2−3+k=0

k=5

Answer 2

$\small \sf \: \: Since \: point \: ( \frac{ - 1}{2} , \frac{1}{3} ) \: lies \: on \: the \: graph \: -2x = 2ay -10 \: \: \: so \: ,$

$\: \: \sf\bold{\red{\sf \: x = \frac{ - 1}{2}, y = \frac{1}{3}}}$

$★\small \sf \: Now \: we \: will \: put \: \: \: \sf\bold{\red{\sf \: x = \frac{ - 1}{2}, y = \frac{1}{3}}} \: in \:\: -2x = 2ay -10 \:$

$⟹ - 2( \frac{ - 1}{2} ) \: = \: 2a( \frac{1}{3} ) - 10$

$⟹\frac{2}{2} = \frac{2a}{3} - 10$

$⟹1 = \frac{2a}{3} - 10$

$⟹1 + 10 = \frac{2a}{3}$

$⟹11 = \frac{2a}{3}$

$⟹\sf \frac{11 \times 3}{2} = a \: \: \: [ Transpose \: ]$

$⟹ \frac{33}{2} = a$

$⟹ \: \sf\bold{\red{a = \frac{33}{2}}}$

Now let's check

$\sf \: We \: will \: put \: a \: as \: \frac{33}{2} \: in \: -2x = 2ay -10 \:$

$⟹ - 2( \frac{ - 1}{2} ) =[ 2 \: \times \: \frac{33}{2} \times \frac{1}{3} ] - 10$

$⟹1 = [33 \times \frac{1}{3} ] - 10$

$⟹1 = 11 - 10$

$⟹1 = 1$

Hence verified

Hence, the correct option is option number c) 33/2

Note :-

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