If a point (1,5)lies on the line x+2y+k=0 then find the value of kj
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Answered by
2
x+2y+k=0
1+10+k=0
k=-11
@Afjal
1+10+k=0
k=-11
@Afjal
Anonymous:
hy
Answered by
2
x = 1
y = 5
Substituting in the equation
1 + 5(2) + k = 0
1+10+ k =0
11+k = 0
k = -11
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