Question

if a point (2,5) lies on a equation 3y+ax=12.find the value of a.​

Answer 1

Answer:

3*2+a*5=12

6+5a=12

5a=6

a=6/5

Answer 2

Step-by-step explanation:

3y+ax=12

putting the values of x and y so

3(5)+a(2)=12

15+2a=12

shift 15 on other side of equility sign it will become negative 15

so

2a=12-15

2a=-3

a=-3/2

verification

put the value of a in equation 3y+ax=12

3(5)+(-3/2)(2)=12

15+(-3)=12

15-3=12

12=12

verified