if a point C lies between two points A and B such that AC = BC, then prove that AC = 1\2AB
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Given that C lies between A and B and AC=BC
So, AC+AC=BC+AC [ according to Euclid's definition, if equals are added to equals, the whole is equal]
i.e., 2AC=AB [BC+AC coincides with AB]
Therefore AC= 1/2 AB.
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