if a point c lies between two points A and B such that AC is equal to, then prove that AC is equal to 1 by 2 AB
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Given that C lies between A and B and AC=BC
So, AC+AC=BC+AC
[ according to Euclid's definition, if equals are added to equals, the whole is equal]
i.e., 2AC=AB
[BC+AC coincides with AB]
Therefore AC=
2
1
AB
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