If a point charge, is placed at the centre of
a cube what is the flux linked (a) with the cube?
(b) with each face of the cube.
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If a point charge is placed at the centre of the cube then:
a) Flux associated with the cube:
According to Gauss Law, ∅ = q/E ......(E=> permittivity)
Thus, Flux linked with the cube = q/E.
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b) Flux associated with each face of the Cube:
Above we have calculated the Flux associated with the whole of the Cube and it came out to be ∅ = q/E.
In other words, we can say that Flux linked with all six(6) faces of the cube is ∅ = q/E.
Thus,
Flux associated with one face of the cube ∅' = ∅/6
=> ∅' = q/6E.
Therefore, flux linked with each face of cube = q/6E.
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