Question

if a point ‘D’ divide line segment AB of length 10cm internally in the ratio 2:3 then find the length of AD​

Answer 1

Question :- if a point ‘D’ divide line segment AB of length 10cm internally in the ratio 2:3 then find the length of AD ?

Answer :-

Let us assume that, D divide the line segment AB in ratio of 2x and 3x respectively .

so,

→ AD + DB = 2x + 3x

→ AB = 5x

→ 10 = 5x

→ x = 2 cm

therefore,

→ AD = 2x

→ AD = 2 * 2 = 4 cm. (Ans.)

Hence, Length of AD will be 4 cm.

Learn more :-

prove that the mid point of the line joining points (-5,12) and (-1,12) is a point of trisection of the line joining the...

https://brainly.in/question/15118408

in what ratio is tge line joining the points (9, 2) and (-3, - 2 ) divided by the y axis? also find the coordinate of th...

https://brainly.in/question/15022879

find the equation of the straight line which passes through the point 4,3 and parallel to line 3x +4y=7

https://brainly.in/question/15527182

Answer 2

SOLUTION

GIVEN

A point ‘D’ divide line segment AB of length 10cm internally in the ratio 2:3

TO DETERMINE

The length of AD

EVALUATION

Here it is given that a point ‘D’ divide line segment AB of length 10cm internally in the ratio 2:3

So the given ratio is 2 : 3

$\displaystyle \sf{ \therefore \: \: Share \: of \: AD \: = \frac{2}{2 + 3} = \frac{2}{5} }$

$\displaystyle \sf{ \therefore \: \: Share \: of \: BD \: = \frac{3}{2 + 3} = \frac{3}{5} }$

Hence

$\displaystyle \sf{ \therefore \: \: Length\: of \: AD \: = 10 \times \frac{2}{5} \: cm= 4 \: cm}$

$\displaystyle \sf{ \therefore \: \: Length\: of \: BD \: = 10 \times \frac{3}{5} \: cm= 6 \: cm}$

FINAL ANSWER

The length of AD = 4 cm

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Find the ratio in which the line segment joining the points (6, 4) and (1, -7) is divided internally by the axis X

https://brainly.in/question/23325742

2. Find the slope of the line perpendicular to the line AB, if A is (3, 3) and B is (-1, 1)

https://brainly.in/question/27031626