if a point moves along a circle with constant speed , ratio of its angular speed
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Let particle move from point A to B on the circumference of the circle in time t. As shown in fig. arc AB makes angle AOB=theta+ beta. From the figure theta=2(phi) and beta=2(alpha).
The angular velocity about center O is
w=(theta+beta)/t…………………..(1)
Thus, w=2(alpha+phi)………………(2)
But, angular velocity about P is
w’=(alpha+phi)………………………..(3)
From (2) and (3),
w=2w’
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2 ( omega )
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