if a point P is equidistant from A(-1,-5) and B(-9,-1) and its abscissa is equal to its ordinate, find the coordinate of the point P
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LET THE CO-ORDINATE OF P BE P(X,2X)
AP=BP
AP^2=BP^2
(X2-X1) +(Y2-Y1) = (X2-X1) +(Y2-Y1)
SUBTITUTE THE VALUES YOU WILL GET THE ANSWER
I HOPE IT IS CLEAR
AP=BP
AP^2=BP^2
(X2-X1) +(Y2-Y1) = (X2-X1) +(Y2-Y1)
SUBTITUTE THE VALUES YOU WILL GET THE ANSWER
I HOPE IT IS CLEAR
vishnutejacp4ejum:
read question properly
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a round solid figure, or its surface, with every point on its surface equidistant from its centre.
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