if a point P lies in the exterior of a circle with center O and raius 3 cm,then
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Answer:
P is in the exterior of ⊙(0.15).
For △PTO,m∠OTP=90
o
OP
2
=OT
2
+PT
2
........... [By Pythagoras theorem]
⟹OP
2
=(15)
2
+(8)
2
=289
∴ OP=17
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