Question

If a point P( x, y ) is at equidistant from ( 7, 1) and ( 3,5), find x and y.​

Answer 1

ANSWER

→ using distance formula

→

(x−7)

2

+(y−1)

2

=

(x−3)

2

+(y−5)

2

⇒−14x+49−2y+1=−6x+9−10y+25

⇒8x−8y=16

⇒x−y=2⇒y=x−2

solution