if a point (x,y)is equidistant from the point (a-b,a+b) and (-a-b,a+b).
prove that x-a =0
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p(x,y) A(a-b,a+b) B(-a-b,a+b)
PA=PB
√(x2-x1)2+(y2-y1)2=√(x2-x1)2+(y2-y1)2
√(a-b-x)2+(a+b-y)2=√(-a-b-x)2+(a+b-y)2
now cancel the square...
(a-b)2+(x)2-2×(a-b)(x)+(a+b)2+(y)2-2(a+b)(y)=(-a-b)2+(x)2-2(-a-b)(x)+(a+b)2+(y)2-2y×(a+b).....
it not done I'll solve tomorrow and send you..
it okay Na
PA=PB
√(x2-x1)2+(y2-y1)2=√(x2-x1)2+(y2-y1)2
√(a-b-x)2+(a+b-y)2=√(-a-b-x)2+(a+b-y)2
now cancel the square...
(a-b)2+(x)2-2×(a-b)(x)+(a+b)2+(y)2-2(a+b)(y)=(-a-b)2+(x)2-2(-a-b)(x)+(a+b)2+(y)2-2y×(a+b).....
it not done I'll solve tomorrow and send you..
it okay Na
yash510:
ok
don't worry...
hmm
(x-a-b)2=(x-(-a-b). =(x)2+(a-b)2-2×x×(a-b)=(x)2+(a+b)2+2x(a+b). =-2x(a-b)=2x(a+b). =-2ax+2bx=2xa+2bx. =-2xa-2xa=2bx-2bx. = -4xa=0. =xa=0. ( i think the question is wrong..
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