If a point(x,y) is equidistant from the points (a+b, b-a) & (a-b, a+b), then prove bx = ay.
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(a+b+a-b/2,b-a+a+b/2)=(x,y)
(a,b)=(x,y)
a/b=x/y
ay=bx
(a,b)=(x,y)
a/b=x/y
ay=bx
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