If a point Z(x, y) is equidistant from K (2, 3) and N (5, 3), then:
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Let the point P(x,y) be equidistant from the points A(5,1) and B(-1,5). then,
PA=PB
PA
2
=PB
2
(x−5)
2
+(y−1)
2
=(x+1)
2
+(y−5)
2
x
2
+y
2
−10x−2y+26=x
2
+y
2
+2x−10y+26
12x−8y=0
12x=8y
3x=2y
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