If a pole 6 m high casts a shadow 2√3 m long on the ground, then the elevation of the sun is??
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Answer:
60 degrees
Step-by-step explanation:
Let height = 6m
length of shadow = 2√3m
ø is angle of elevation
Tanø= height/shadow length
= 6/2√3=√3
ø=π/3
Angle of elevation is =60°
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