Question

If a pole of 12 m high casts a shadow 4√3 long on the ground then the sun’s elevation is (a) 60° (b) 45° (c) 30° (d) 90°

Answer 1

Answer:

Hope it helps!!!

Answer 2

The sun’s elevation is 60°

Step-by-step explanation:

Height of pole = Perpendicular=12 m

Length of shadow = Base = $4\sqrt{3}$

$Tan \theta =\frac{Perpendicular}{Base}$

$Tan \theta =\frac{12}{4\sqrt{3}}$

$tan \theta = \frac{3}{\sqrt{3}}$

$Tan \theta= \sqrt{3}$

$\theta = tan^{-1}\sqrt{3}$

$\theta = 60^{\circ}$

Hence the sun’s elevation is 60°

#Learn more:

A pole 6 m high casts a shadow 2√3 m long on the ground, then the Sun’s elevation is (A) 60° (B) 45° (C) 30° (D) 90°

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