Question

If a polygon has 27 diagonals . How many sides does it have ?

Answer 1

Answer:

9

Step-by-step explanation:

for a polygon having n vertices

no of diagonals = n*(n-3)/2

n vertices form n sides

n*(n-3)/2 = 27

n*(n-3)=54

n²-3n-54=0

n²-9n+6n-54=0

n(n-9)+6(n-9)=0

n=9 and -6

-6 sides is not possible so ans is 9