if a polygon has 44 diangnals.find no. of sides
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may be answer of this question is 11
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formula for diagonal of n sides=1/2*n*(n-3)
no.of diagonals =44
1/2*n*(n-3)=44
n^2-3n=88
n^2-3n-88=0
n^2-11n+8n-88=0
n (n-11)+8 (n-11)=0
(n-11)(n+8)=0
n=11 or -8
but sides are always positive. so
no. of sides =11.
pls mark the ans as brainliest.
no.of diagonals =44
1/2*n*(n-3)=44
n^2-3n=88
n^2-3n-88=0
n^2-11n+8n-88=0
n (n-11)+8 (n-11)=0
(n-11)(n+8)=0
n=11 or -8
but sides are always positive. so
no. of sides =11.
pls mark the ans as brainliest.
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