if a polygon of "n"sides has 1/2n(n-3) diagonals. How many sides will a polygon having 65 diagonals?Is there any polygon with 50 diagonals?
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simply putt
n(n-3)/2=65
re-arrange
n^2-3n-130=0
appply
quadratic formula or simply make factors
u will have
n=13 or n=-10(not possible)
n(n-3)/2=65
re-arrange
n^2-3n-130=0
appply
quadratic formula or simply make factors
u will have
n=13 or n=-10(not possible)
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