If a polynomial leaves remaindes 3 and 2
when divided by (x+2) and (x+1) respectively
find on remainder obtained when it is
divided by x²+3x+2
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f(-2)=3, so f(-2)+1=4, so the remainder of f(x)+1 divided by (x+2) is 4. Similarly, 2f(-2)=6, so the remainder of 2f(x) divided by (x+2) is 6.
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