If a polynomial p(x) = x^2 - ax + b has two zeroes 1 and 7, what
is the value of ab?
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Answer:
a=8 and b=-7
Step-by-step explanation:
f(1)=x^2-ax+b
=1-a+b
a+b=1...(1)
f(7)= 49-7a+b
7a+b=49...(2)
from equation (1)and (2) , we get
a=8
b=-7
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