Question

if a polynomial x4-3x3-8x2+12x+16 has two zeros as -1 and 4 then find the other zeros​

Answer 1

Answer:  All the zeroes are -1, 4, 2 and -2

Step-by-step explanation:

f(x) = x⁴-3x³-8x²+12x+16

Given that -1 and 4 are zeroes,

x+1  and  x-4  are factors.

(x+1)(x-4) = x²-3x-4

g(x) = x²-3x-4

On dividing f(x) by g(x) using long division method, we get

q(x) = x²-4

=> x² - 2²

=> (x-2) (x+2)                           [a²-b² = (a-b) (a+b)]

=> x = 2 or -2

Therefore the zeroes of f(x) are -1, 4, 2 and -2

Hope it helps.....

Answer 2

Answer:

I have done it. Hope it helps.