Question

if a polynomial xpower3 - 6x power2 + 9x +3 is divided by x-1,then the remainder is a 11 b7 c10 d8​

Answer 1

Answer:

vdieveec rirve3 4brir irveij33 eirvrir ejevrir rjr hr 4urvrur rurvri

Answer 2

Answer:

Dividend=x

3

−6x

2

+9x+3

\text{Divisor=$x-1$}Divisor=x−1

Step-by-step explanation:

The remainer when P(x) is divided by (x-a) is P(a)

\text{Let}\;P(x)=x^3 -6x^2+9x+3LetP(x)=x

3

−6x

2

+9x+3

\text{Using remainder theorem,}Using remainder theorem,

\text{The remainder when $P(x)$ is divided by $x-1$}The remainder when P(x) is divided by x−1

=P(1)=P(1)

=1^3 -6(1)^2+9(1)+3=1

3

−6(1)

2

+9(1)+3

=1-6+9+3=1−6+9+3

=13-6=13−6

=7