Biology, asked by pawarrutuja125, 9 months ago

if a population has dominant phenotype in 1600 individual out of 2000 then calculate the frequency of heterozygate

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Answered by lxm1857

Explanation:

since we believe that the homozygous recessive for this gene (q²) represent 4% ( i.e.= 0.04) the square root (q) is 0.2 and (20%).

The frequency of the dominant allala. answers : since q=0.2, and p+q=1, than p=0.8(80%).the frequency of hetorozygous India.

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Answered by Anonymous

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sɪɴᴄᴇ ᴡᴇ ʙᴇʟɪᴇᴠᴇ ᴛʜᴀᴛ ᴛʜᴇ ʜᴏᴍᴏᴢʏɢᴏᴜs ʀᴇᴄᴇssɪᴠᴇ ғᴏʀ ᴛʜɪs ɢᴇɴᴇ (ϙ²) ʀᴇᴘʀᴇsᴇɴᴛ 4% ( ɪ.ᴇ.= 0.04) ᴛʜᴇ sϙᴜᴀʀᴇ ʀᴏᴏᴛ (ϙ) ɪs 0.2 ᴀɴᴅ (20%).

ᴛʜᴇ ғʀᴇϙᴜᴇɴᴄʏ ᴏғ ᴛʜᴇ ᴅᴏᴍɪɴᴀɴᴛ ᴀʟʟᴀʟᴀ. ᴀɴsᴡᴇʀs : sɪɴᴄᴇ ϙ=0.2, ᴀɴᴅ ᴘ+ϙ=1, ᴛʜᴀɴ ᴘ=0.8(80%).ᴛʜᴇ ғʀᴇϙᴜᴇɴᴄʏ ᴏғ ʜᴇᴛᴏʀᴏᴢʏɢᴏᴜs ɪɴᴅɪᴀ.

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if a population has dominant phenotype in 1600 individual out of 2000 then calculate the frequency of heterozygate