Question

If a position of a particle at instant t is given by x is equal to 3 T square find the velocity and acceleration of the particle

Answer 1

Answer:

We have x(t)=4t

3

−3t

2

+2

⇒v=

dt

dx

=12t

2

−6t

and a=

dt

dv

=24t−6

∴v at t=2s is 12(2)

2

−6(2) i.e., 36ms

−1

and a at t=2s is 24×2−6 i.e., 42ms

−2