Physics, asked by saumyasingh338, 11 months ago

If a positive charge is displaced against the electric field in which it was
situated, then
(A)
work will be done by the electric field on the charge.
(B)
the intensity of the electric field decreases.
(C)
energy of the system will decrease.
(D)
energy will be provided by external source displacing the charge.

Answers

Answered by gubbalavidyasagar563
30

Answer:

Answer is A

potential difference

Answered by mad210202
10

If positive charge is displaced against the electric  field in which it was situated ,then  work will be done by electric field on the charge it will be option A.        

Explanation:      

  • Electric field intensity at any point is defined as the force experienced by a unit positive charge placed at the point.
  • The electric field intensity is a vector quantity. electric field due to a positive charge is always away from the charge and that due to to a negative charge is always towards the charge.
  • In an electric field E a charge Q experiences a force F= Q.E. if charge is positive than force is directed to the direction of field while if charge is negative force acts on it in the opposite direction of a field .
  • so, if a positive charge is displaced against the electric field in which it was situated then work will be done by the electric field on the charge.
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