If a positive number exceeds its positive square root by 12 then find the number
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16 is the answer
As now we have from given information x = x^(1/2) +12
let us consider x^(1/2) = t
then according to the equation t^2=t+12
ie. t^2 - t - 12 =0
factorizing we get (t+3)(t-4)=0,
As we here consider only positive values we get ,
t = 4 , ie. x^(1/2) = 4
x = 4^2
x = 16
As now we have from given information x = x^(1/2) +12
let us consider x^(1/2) = t
then according to the equation t^2=t+12
ie. t^2 - t - 12 =0
factorizing we get (t+3)(t-4)=0,
As we here consider only positive values we get ,
t = 4 , ie. x^(1/2) = 4
x = 4^2
x = 16
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